Question 182550: Quadratic Function
Find the a: vertex
b: domain
c: range
of f(x) = -2x^2 - 4x +3 Found 2 solutions by stanbon, solver91311:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Quadratic Function
Find the a: vertex
b: domain
c: range
of f(x) = -2x^2 - 4x +3
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Put in vertex form:
2x^2 + 4x + ? = -y + 3 + ?
2(x^2+2x + 1) = -y + 3 + 2
2(x+1)^2 = -y + 5
(x+1)^2 = (-1/2)y + (5/2)
(x+1)^2 = (-1/2)(y - 5)
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Vertex: (-1,5)
domain: all Real Numbers
Range: all Real Numbers <= 5
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Cheers,
Stan H.
So, calculate to obtain the x-coordinate of the vertex, then calculate the value of your function at that x-coordinate value to obtain the y-coordinate of the vertex.
If then the parabola opens upward and the vertex is a minimum.
If then the parabola opens downward and the vertex is a maximum.
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