SOLUTION: I have a 4 by 4 system of equation that I'm trying to solve using a matrix. I'm very stuck on the row reduction. Please help. Here are my equations: a+b+2c+d=14 2a-b-c+d=8 a+2

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: I have a 4 by 4 system of equation that I'm trying to solve using a matrix. I'm very stuck on the row reduction. Please help. Here are my equations: a+b+2c+d=14 2a-b-c+d=8 a+2      Log On


   

Question 182497: I have a 4 by 4 system of equation that I'm trying to solve using a matrix.
I'm very stuck on the row reduction. Please help.
Here are my equations:
a+b+2c+d=14
2a-b-c+d=8
a+2b+c-d=15
3a-2b+3c+2d=24
and this is the matrix I have so far (sorry, I'm not sure how to put the brackets):
[1 1 2 1] [14]
[2 -1 -1 1] [8]
[1 2 1 -1] [15]
[3 -2 3 2] [24]
Please help me. This is due today. I've been working on it all night.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Check out this link to see the solution which was generated by the Linear Algebra Toolkit

Notice how the right hand column of the last step has the values (from top to bottom): 7, 2, 3, -1

So this tells us that the solutions are

a=7, b=2, c=3, and d=-1