SOLUTION: A cash box contained $12.25 in quarters, dimes, and nickels. If there were five more than twice as many dimes as nickels and one less than three times as many quarters as nickels,

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Question 18243: A cash box contained $12.25 in quarters, dimes, and nickels. If there were five more than twice as many dimes as nickels and one less than three times as many quarters as nickels, how many of each kind of coin was there?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Let number of nickels be "x".
Then number of dimes = 2x+5
And number of quarters = 3x-1
Value of nickels is 5x cents
Value of dimes is 10(2x+5) = 20x+50 cents
Value of quarters = 25(3x-1) = 75x-25 cents
Equation:
Value of nickels + value of dimes + value of quarters = 1225 cents
5x+20x+50+75x-25 = 1225
100x = 1200
x= 12 (number of nickels)
2x+5 = 29 (number of dimes)
3x-1 = 35 (number of quarters)
Cheers,
Stan H.