SOLUTION: please help with polynomial (3x+4) ^2 thank you

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Question 182424: please help with polynomial

(3x+4) ^2 thank you
Found 2 solutions by Mathtut, jim_thompson5910:
Answer by Mathtut(3670) About Me  (Show Source):
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

%283x%2B4%29%5E2 Start with the given expression.


%283x%2B4%29%283x%2B4%29 Expand. Remember something like x%5E2=xx.


Now let's FOIL the expression.


Remember, when you FOIL an expression, you follow this procedure:


%28highlight%283x%29%2B4%29%28highlight%283x%29%2B4%29 Multiply the First terms:%283x%29%283x%29=9x%5E2.


%28highlight%283x%29%2B4%29%283x%2Bhighlight%284%29%29 Multiply the Outer terms:%283x%29%284%29=12x.


%283x%2Bhighlight%284%29%29%28highlight%283x%29%2B4%29 Multiply the Inner terms:%284%29%283x%29=12x.


%283x%2Bhighlight%284%29%29%283x%2Bhighlight%284%29%29 Multiply the Last terms:%284%29%284%29=16.


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So we have the terms: 9x%5E2, 12x, 12x, and 16


9x%5E2%2B12x%2B12x%2B16 Now collect every term listed above to make a single expression.


9x%5E2%2B24x%2B16 Now combine like terms.


So %283x%2B4%29%5E2 FOILs to 9x%5E2%2B24x%2B16.


In other words, %283x%2B4%29%5E2=9x%5E2%2B24x%2B16.