SOLUTION: This is from a book. Marta has $6000 to invest. She puts X dollars of this money into a savings account that earns 3% per year, and with the rest, she buys a certificate of depos

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Question 182418This question is from textbook Algebra 1
: This is from a book. Marta has $6000 to invest. She puts X dollars of this money into a savings account that earns 3% per year, and with the rest, she buys a certificate of deposit that earns 6% per year. Write an equation for the total amount of money T Marta will have after one year.
I tried this.
T = 6000X (3%) + (6000- 180x)(6%)
6000X (.03)
180X + (360-10.8X)
Thanks for the help This question is from textbook Algebra 1

Found 2 solutions by stanbon, Mathtut:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Marta has $6000 to invest. She puts X dollars of this money into a savings account that earns 3% per year, and with the rest, she buys a certificate of deposit that earns 6% per year. Write an equation for the total amount of money T Marta will have after one year.
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Equation:
Total = principal + interest + interest
Total = 6000 + 0.03x + 0.06(6000-x)
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Cheers,
Stan H.

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
This is from a book. Marta has $6000 to invest. She puts X dollars of this money into a savings account that earns 3% per year, and with the rest, she buys a certificate of deposit that earns 6% per year. Write an equation for the total amount of money T Marta will have after one year.
I tried this.
T = 6000X (3%) + (6000- 180x)(6%)
6000X (.03)
180X + (360-10.8X)
:
when you multiply x by 6000......your muliplying by the portion of 6000 dollars that is invested at 3%. Let try this another way
:
lets call x the amount she put into the savings at 3%
lets call y the amount she put into cd at 6%
:
we know that x+y=6000 therefore we know that y=6000-x
:
total amount after 1 year lets call t
:
T=6000+.03x+.06y
:
T=6000+(.03x+.06(6000-x))
:
T=6000+.03x+360-.06x
:
T=6360-.03x