SOLUTION: A computer store sold 300 items last month. The store sold 6 times as many hard drives as they did CD-ROM drives, and half as many floppy drivs as hard drives. Based on this infor
Algebra ->
Customizable Word Problem Solvers
-> Finance
-> SOLUTION: A computer store sold 300 items last month. The store sold 6 times as many hard drives as they did CD-ROM drives, and half as many floppy drivs as hard drives. Based on this infor
Log On
Question 182307: A computer store sold 300 items last month. The store sold 6 times as many hard drives as they did CD-ROM drives, and half as many floppy drivs as hard drives. Based on this informatin, how many of each item was sold? Found 2 solutions by josmiceli, J2R2R:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = number of hard drives sold
Let = number of CD-ROMs sold
Let = number of floppy drives sold
given:
(1)
(2)
(3)
--------------------
(1)
(2)
Substitute in (1):
(1)
and
also
(3)
180 hard drives, 30 CD-ROM drives, and 90 floppy drives were sold
You can put this solution on YOUR website! A computer store sold 300 items last month.
The store sold 6 times as many hard drives as they did CD-ROM drives and half as many floppy drives as hard drives.
Based on this information, how many of each item was sold?
Number of Hard Drives = A
Number of CD Rom drives = B
Number of Floppy Drives = C
A + B + C = 300
The store sold 6 times as many hard drives as they did CD-ROM drives:
A = 6B
The store sold half as many floppy drives as hard drives:
C = A/2 (= 3B from above)
Writing A + B + C = 180 in terms of B for A and C:
6B + B + 3B = 300
10B = 300
B = 30 CD Rom drives
A = 180 Hard Drives
C = 90 Floppy Drives
