SOLUTION: Pam has brown eyes and Bob has blue eyes. Brown genes B are dominant over blue eyes b. A person with genes BB or Bb has brown eyes. Someone with genes bb has blue eyes. Suppose Pam

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Pam has brown eyes and Bob has blue eyes. Brown genes B are dominant over blue eyes b. A person with genes BB or Bb has brown eyes. Someone with genes bb has blue eyes. Suppose Pam      Log On


   



Question 182246: Pam has brown eyes and Bob has blue eyes. Brown genes B are dominant over blue eyes b. A person with genes BB or Bb has brown eyes. Someone with genes bb has blue eyes. Suppose Pam's genes for eye color are Bb.
a. Write an expression for the possible eye coloring of Pam and Bob's children.
b. What is the probability that a child of Pam and bob would have blue eyes?
Please help! I tried it, but I don't know if I am right. For A, I have no idea how to do that. For B, I have 3/4 b, but i'm not sure if i'm right.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Pam has brown eyes and Bob has blue eyes. Brown genes B are dominant over blue eyes b. A person with genes BB or Bb has brown eyes. Someone with genes bb has blue eyes. Suppose Pam's genes for eye color are Bb.
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a. Write an expression for the possible eye coloring of Pam and Bob's children.
From Bob: b or b
From Pam: b or B
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Expression for possible eye coloring: bb(blue),bb(blue),bB(brown),bB(brown)
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b. What is the probability that a child of Pam and bob would have blue eyes?
2/4 = 1/2
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Chers,
Stan H.