SOLUTION: Hi my name is jason and i dont have problems out of a text book but in a packet that my teacher had given me on Friday. Im on a section that has to deal with absolute value signs.

Algebra ->  Absolute-value -> SOLUTION: Hi my name is jason and i dont have problems out of a text book but in a packet that my teacher had given me on Friday. Im on a section that has to deal with absolute value signs.       Log On


   

Question 182202: Hi my name is jason and i dont have problems out of a text book but in a packet that my teacher had given me on Friday. Im on a section that has to deal with absolute value signs.
/3z/+7=10
(Solving for z)
I have no clue how to do that why i have been thinking is i take 7 and subtract it from the ten since its positive (our teacher has taught us that what ever you do to one side you must do to the other) so that gives me:
/3z/=3
so do i just divide 3 from both sides to get:
z=1
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for z:
abs%283z%29%2B7+=+10 First, subtract 7 from both sides of the equation to isolate the absolute value.
abs%283z%29+=+3 Now remove the absolute-value bars abd write the two resulting equations:
3z+=+3 or 3z+=+-3 Now divide both sides by 3 in these two equations:
z+=+1 or z+=+-1
Check:
abs%283z%29%2B7+=+10 First substitute z = 1.
abs%283%2A1%29%2B7+=+10 Evaluate the left side.
3%2B7+=+10
10+=+10 OK!
abs%283z%29%2B7+=+10 Substitute z = -1.
abs%283%28-1%29%29%2B7+=+10
abs%28-3%29%2B7+=+10 Evaluate the left side.
3%2B7+=+10
10+=+10 OK!