SOLUTION: A moving truck leaves the house at a steady rate of 40mph. The family leaves the house 1 hour later following the same route in a car. They travel at a steady rate of 60mph. How lo
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Question 182097This question is from textbook pre-algebra
: A moving truck leaves the house at a steady rate of 40mph. The family leaves the house 1 hour later following the same route in a car. They travel at a steady rate of 60mph. How long after the moving truck leaves the house will the car catch up with the truck? This question is from textbook pre-algebra
You can put this solution on YOUR website! A moving truck leaves the house at a steady rate of 40mph. The family leaves the house 1 hour later following the same route in a car. They travel at a steady rate of 60mph. How long after the moving truck leaves the house will the car catch up with the truck?
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Truck DATA:
rate = 40 mph ; distance = x miles ; time = d/r = x/40 hrs.
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Car DATA:
rate = 60 mph ; distance = x miles ; time = d/r = x/60 hrs.
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Equation:
truck time - car time = 1 hr
x/40 - x/60 = 1
Multiply thru by 120 to get;
3x - 2x = 120
x = 120 miles (distance)
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Car time = x/60 = 120/60 = 2 hrs.
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Cheers,
Stan H.
You can put this solution on YOUR website! A moving truck leaves the house at a steady rate of 40mph. The family leaves the house 1 hour later following the same route in a car. They travel at a steady rate of 60mph. How long after the moving truck leaves the house will the car catch up with the truck?
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The truck moves 40 miles in the hour.
The relative speed is 60-40, = 20 mph, so it will take 2 hours to catch up, or 3 hours after the truck leaves.
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