Question 182014This question is from textbook
: Consider the problem:
x-8 divided by x-9
____ ____
x+5 x+4
Explain wny -5, 9,-4 are not an allowable replacement for the variable x.
Thankyou
This question is from textbook
Answer by ilana(307)   (Show Source):
You can put this solution on YOUR website! So it looks like your expression is [(x-8)/(x+5)]/[(x-9)/(x+4)].
x cannot be -5 because then (x-8)/(x+5) would be -13/0, so 0 would be the denominator, which make that fraction undefined.
x cannot be -4 because then (x-9)/(x+4) would be -13/0, so 0 would be the denominator, which make that fraction undefined.
x cannot be 9 because then [(x-8)/(x+5)]/[(x-9)/(x+4)] would be (1/14)/(0/13), which equals (1/14)/0, so 0 would be the denominator, which make that fraction undefined.
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