You can put this solution on YOUR website! any straight line can be sketched if you know it in the form y = mx + c where m is the gradient and c in the y-intercept...so we need to re-arrange your equation slightly
becomes then becomes which is .
so, the gradient is -2/3 and the y-intercept is at y=2
We can also find where the line crosses the x-axis, as this is where y=0, so putting y=0 into the equation (any version) gives x=3.
You need to know what a +ve and -ve gradient looks like:
+ve is /
-ve is \
cheers
Jon
