SOLUTION: Find three consecutive positive even integers such that the sum of their squares is 980.

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Question 181922: Find three consecutive positive even integers such that the sum of their squares is 980.
Answer by Alan3354(69443) About Me  (Show Source):
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Find three consecutive positive even integers such that the sum of their squares is 980.
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There are 2 ways to do this.
The easy way:
Since the numbers are close, each is about 1/3 of the total.
980/3 =~ 326. The square root of 326 is just over 18 (18^2 = 324).
So 18 is the middle number, and they're 16, 18 and 20.
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The hard way:
x%5E2+%2B+%28x%2B2%29%5E2+%2B+%28x%2B4%29%5E2+=+980
3x%5E2+%2B+12x+%2B+20+=+980
3x%5E2+%2B+12x+-+960+=+0
(3x+60)*(x-16) = 0
x = 16, x = -20
It says positive, so it's 16, 18 & 20