SOLUTION: (2a^6 b^3)(3^2 a^-2 b^5)/36a^4 how do you handle the two sections of the brackets? how do you calculate them?

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Question 181904: (2a^6 b^3)(3^2 a^-2 b^5)/36a^4
how do you handle the two sections of the brackets? how do you calculate them?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
%28%282a%5E6%2Ab%5E3%29%283%5E2%2Aa%5E-2%2Ab%5E5%29%29%2F%2836a%5E4%29
Since everything is multiply, the brackets don't matter, just get rid of them
%282a%5E6%2Ab%5E3%2A3%5E2%2Aa%5E-2%2Ab%5E5%29%2F%2836a%5E4%29
You can cancel a^4 in the denominator into a^6 in the numerator, square 3
%282a%5E2%2Ab%5E3%2A9%2Aa%5E-2%2Ab%5E5%29%2F%2836%29
Cancel 9 into 36
%282a%5E2%2Ab%5E3%2Aa%5E-2%2Ab%5E5%29%2F4
cancel 2 into 4
%28a%5E2%2Ab%5E3%2Aa%5E-2%2Ab%5E5%29%2F2
:
Combine the exponents of like terms
%28a%5E%28%282-2%29%29%2Ab%5E%28%283%2B5%29%29%29%2F2
%28a%5E0%2Ab%5E8%29%2F2
anything to the power of 0 = 1
%281b%5E8%29%2F2 or just %28b%5E8%29%2F2