Question 181879: Harry saved nickels, dimes, and quarters in a jar. When the jar was full, he counted the money. He had as many quarters as dimes, but he had twice as many nickels as dimes. If the jar had 844 coins, how much money had Harry saved?
This is an open ended writing response and I have no idea how to begin to solve this. I am in the seventh grade.
Found 2 solutions by eperette, ankor@dixie-net.com:
Answer by eperette(173)   (Show Source):
You can put this solution on YOUR website!
Given:
q=d
n=2d
n+d+q=844
2d + d + d=844
4d = 844
d = 211
q = 211
n = 211(2)
n=422
So he had:
211(0.10) + 211(0.25) + 422(.05)
21.10 + 52.75 + 21.10
94.95
Answer by ankor@dixie-net.com(22740)  (Show Source):
You can put this solution on YOUR website! Harry saved nickels, dimes, and quarters in a jar. When the jar was full, he
counted the money. He had as many quarters as dimes, but he had twice as many
nickels as dimes. If the jar had 844 coins, how much money had Harry saved?
:
Let x = no. of dimes
then
x = no. of quarters also
and
2x = no. of nickels
:
nickels + dimes + quarters = 844
2x + x + x = 844
:
4x = 844
x = 
x = 211 dimes
:
then we have
211 quarters
and
422 nickels
;
How much $
.05(422) + .10(211) + .25(211) =
21.10 + 21.10 + 52.75 = $94.95
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