Question 181619: Hi I need some help with the following problem .
Solve each system by any method.
{2/3x-1/4y=-8
1/2x-3/8y=-9
Answer by HyperBrain(694)   (Show Source):
You can put this solution on YOUR website! I hate dealing with fractions, so let's make the coefficients integral.
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2/3x-1/4y=-8
12(2/3x-1/4y)=12(-8)
[1]8x-3y=-96
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1/2x-3/8y=-9
8(1/2x-3/8y)=8(-9)
[2]4x-3y=-72
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Subtracting [2] from [1],
4x=-24
4x/4=-24/4
x=-6
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Using [1],
8(-6)-3y=-96
-48-3y=96
-3y=-48
y=16
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Therefore, x=-6, y=16
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