Question 181551: Find an Equation of the line that satisfies the given conditions.
through (-1, -12); perpendicular to the line passing through (2, 0) and (6, -2)
y=___________
cant figure this out...help! thanks
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Find an Equation of the line that satisfies the given conditions.
through (-1, -12); perpendicular to the line passing through (2, 0) and (6, -2)
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First, find the slope, m, of the line.
m = (diffy)/(diffx)
m = (-2-0)/(6-2)
m = -2/4
m = -1/2
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Lines parallel will have the same slope.
Lines perpendicular will have a slope that's the negative inverse, +2.
Then use
y-y1 = m*(x-x1) where (x1,y1) is the point (-1,-12)
y+12 = 2*(x+1)
y+12 = 2x+2
y = 2x - 10
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