SOLUTION: y=xsquared+8x+12 Find the vertex, y intercept, and x intercept, and axis of symmetry and symmetric point in standard vertex form.

Algebra ->  Average -> SOLUTION: y=xsquared+8x+12 Find the vertex, y intercept, and x intercept, and axis of symmetry and symmetric point in standard vertex form.       Log On


   

Question 181412: y=xsquared+8x+12
Find the vertex, y intercept, and x intercept, and axis of symmetry and symmetric point in standard vertex form.
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
y=x%5E2%2B8x%2B12%29
:
first you have to complete the square
:
y=%28x%5E2%2B8x%2B16%29-16%2B12
:
y=%28x%2B4%29%5E2-4
:
so the vertex is (-4,-4)
:
axis of symmetry is x=-4
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y intercept is found by setting x =0--->y=0+0+12=12
so y intercept is 12--->(0,12)
:
x intercept is found by setting y =0
:
x%5E2%2B8x%2B12%2B0
:
%28x%2B2%29%28x%2B6%29=0
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so x intercepts are at -2 and -6--->(-2,0) and (-6,0)
:
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28x%2B4%29%5E2-4%29