Question 181094This question is from textbook
: Find the amplitude, the period, and the phase shift for the given equation.For any fractions, enter as 'a/b' with no spaces.
y = -5*sin(x/5 - Pi/2)
This question is from textbook
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Find the amplitude, the period, and the phase shift for the given equation.For any fractions, enter as 'a/b' with no spaces.
y = -5*sin(x/5 - Pi/2)
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These are all the same.
The peak-to-peak amplitude is + and 1 the coefficient, for this one it's +/-5.
The period is the inverse of the coefficient of the variable, x, times 2pi, so for this one it's 5*2pi = 10pi.
The phase shift is the negative of the additive term, so this one is +pi/2 radians.
You can DL software at http://www.padowan.dk/graph/ and see how these look.
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