SOLUTION: Joe has a collection of nickles and dimes that is worth $6.05. If the number of dimes was doubled and the number of nickles was decreased by 10,the vlue of th ecoins would be $9.8

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Joe has a collection of nickles and dimes that is worth $6.05. If the number of dimes was doubled and the number of nickles was decreased by 10,the vlue of th ecoins would be $9.8      Log On


   



Question 181025: Joe has a collection of nickles and dimes that is worth $6.05. If the number of dimes was doubled and the number of nickles was decreased by 10,the vlue of th ecoins would be $9.85. How many dimes does he have?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let n = the number of nickels
Let d = the number of dimes
given:
10%2A%282d%29+%2B+5%2A%28n+-+10%29+=+985 (in pennies)
20d+%2B+5n+-+50+=+985
(1) 5n+%2B+20d+=+1035
(2) 5n+%2B+10d+=+605
Subtract (2) from (1)
(1) 5n+%2B+20d+=+1035
(2) -5n+-+10d+=+-605
10d+=+430
d+=+43
He has 43 dimes
And, since
(2) 5n+%2B+10d+=+605
5n+%2B+430+=+605
5n+=+175
n+=+35
check answer:
(1) 5n+%2B+20d+=+1035
5%2A35+%2B+20%2A43+=+1035
175+%2B+860+=+1035
1035+=+1035
OK