Question 181008: A survey showed that 24% of college students read newspapers on a regular basis and that 82% of college students regularly watch the news on TV. The survey also showed that 21% of college students both follow TV news regularly and read newspapers regularly.
(a) What is the probability that a student watches TV news regularly, given that he or she regularly reads newspapers? Round your answer to 2 decimal places.
(b) What is the probability that a randomly selected college student reads newspapers regularly, given that he or she watches TV news regularly? Round your answer to 2 decimal places.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A survey showed that 24% of college students read newspapers on a regular basis and that 82% of college students regularly watch the news on TV.
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The survey also showed that 21% of college students both follow TV news regularly and read newspapers regularly.
(a) What is the probability that a student watches TV news regularly, given that he or she regularly reads newspapers? Round your answer to 2 decimal places.
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Ans: P(watches TV|reads newspapers) = [P(TV and newspapers)/P(newspapers)
= 0.21/0.24 = 0.875
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(b) What is the probability that a randomly selected college student reads newspapers regularly, given that he or she watches TV news regularly? Round your answer to 2 decimal places.
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Ans: P(newspapers | watches TV) = [P(newspapers and TV)] / P(TV)
= 0.21/0.82 = 0.2561...
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Cheers,
Stan H.
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