SOLUTION: Mary has $4.40 in nickles,dimes and quarters. She has four more dimes than quarters and twice as many nickles as dimes. How many coins of each type does she have?

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Question 180987This question is from textbook College Algebra
: Mary has $4.40 in nickles,dimes and quarters. She has four more dimes than quarters and twice as many nickles as dimes. How many coins of each type does she have? This question is from textbook College Algebra

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let n = number of nickels
Let d = number of dimes
Let q = number of quarters
given:
(1) d+=+q+%2B+4
(1) q+=+d+-+4
(2) n+=+2d
(3) 5n+%2B+1d+%2B+25q+=+440 (in cents)
Substitute d-4 in (1) and 2d in (2) for
q and n in (3)
(3) 5%282d%29+%2B+1d+%2B+25%28d+-+4%29+=+440
10d+%2B+d+%2B+25d+-+100+=+440
36d+=+540
d+=+15
and
(1) q+=+d+-+4
q+=+15+-+4
q+=+11
and
(2) n+=+2d
n+=+2%2A15
n+=+30
She has 30 nickels, 15 dimes, and 11 quarters
check:
(3) 5n+%2B+1d+%2B+25q+=+440 (in cents)
5%2A30+%2B+15+%2B+25%2A11+=+440
150+%2B+15+%2B+275+=+440
440+=+440
OK