Question 180823: Suppose that the New England Colonials baseball team is equally likely to win a game as not to win it. If 5 Colonials games are chosen at random, what is the probability that exactly 4 of those games are won by the Colonials?
Round your response to at least three decimal places.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Suppose that the New England Colonials baseball team is equally likely to win a game as not to win it. If 5 Colonials games are chosen at random, what is the probability that exactly 4 of those games are won by the Colonials?
Round your response to at least three decimal places.
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P(win) = 1/2 = P(lose)
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Your problem is binomial with n=5,p=1/2,x = 4
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Answer: P(x=4) = 5C4(1/2)^4(1/2) = 5(1/2)^5 = 5/32
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Cheers,
Stan H.
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