SOLUTION: f(x)=-3x^2 + 5x If f(x)=-2, what is x? What point(s) are on the graph of f? My understanding>>> -2=-3x^2+5x 0=-3x^2+5x+2 Factor it (I believe this is where I am mes

Algebra ->  Rational-functions -> SOLUTION: f(x)=-3x^2 + 5x If f(x)=-2, what is x? What point(s) are on the graph of f? My understanding>>> -2=-3x^2+5x 0=-3x^2+5x+2 Factor it (I believe this is where I am mes      Log On


   



Question 180578This question is from textbook Sullivan Algebra and Trigonoetry
: f(x)=-3x^2 + 5x

If f(x)=-2, what is x? What point(s) are on the graph of f?

My understanding>>>
-2=-3x^2+5x
0=-3x^2+5x+2
Factor it (I believe this is where I am messing up)
0= (??_ ??)(??_??)
Set both to zero
0= (??_??) 0=(??_??)
Solve for each.
Am I using the right process to solve for x?
How do I factor this properly? (my signs are not comming out right when I foil my answer to check it)
How would I determine my domain after I have determined the value of x?
This question is from textbook Sullivan Algebra and Trigonoetry

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
It looks like you have a good understanding of what you are doing. It seems that the only thing that is hanging you up is the factoring.


So let's factor -3x%5E2%2B5x%2B2


-3x%5E2%2B5x%2B2 Start with the given expression.


-%283x%5E2-5x-2%29 Factor out a negative 1 (to make the leading coefficient positive; this isn't required, but it helps)

----------------------------------------------------

Now let's factor the inner expression 3x%5E2-5x-2


Looking at the expression 3x%5E2-5x-2, we can see that the first coefficient is 3, the second coefficient is -5, and the last term is -2.


Now multiply the first coefficient 3 by the last term -2 to get %283%29%28-2%29=-6.


Now the question is: what two whole numbers multiply to -6 (the previous product) and add to the second coefficient -5?


To find these two numbers, we need to list all of the factors of -6 (the previous product).


Factors of -6:
1,2,3,6
-1,-2,-3,-6


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -6.
1*(-6)
2*(-3)
(-1)*(6)
(-2)*(3)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -5:


First NumberSecond NumberSum
1-61+(-6)=-5
2-32+(-3)=-1
-16-1+6=5
-23-2+3=1



From the table, we can see that the two numbers 1 and -6 add to -5 (the middle coefficient).


So the two numbers 1 and -6 both multiply to -6 and add to -5


Now replace the middle term -5x with x-6x. Remember, 1 and -6 add to -5. So this shows us that x-6x=-5x.


3x%5E2%2Bhighlight%28x-6x%29-2 Replace the second term -5x with x-6x.


%283x%5E2%2Bx%29%2B%28-6x-2%29 Group the terms into two pairs.


x%283x%2B1%29%2B%28-6x-2%29 Factor out the GCF x from the first group.


x%283x%2B1%29-2%283x%2B1%29 Factor out 2 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28x-2%29%283x%2B1%29 Combine like terms. Or factor out the common term 3x%2B1


---------------------------------------------

So this means that -%283x%5E2-5x-2%29 factors further down to -%28x-2%29%283x%2B1%29


=============================================


Answer:


So -3x%5E2%2B5x%2B2 completely factors to -%28x-2%29%283x%2B1%29.


Now from here, simply set each factor equal to zero and solve for "x"