You can put this solution on YOUR website! re write these in slope intercept form y=mx+b
:
-18y=3x+6--->y=(-1/6)x-(1/3)........eq 1
:
-y=-6x+14--->y=6x-14................eq 2
:
The slope in eq 1 is -1/6 and the slope in eq 2 is 6. These are negative recipricals of each other therefore these are
:
perpendicular lines
You can put this solution on YOUR website! You can solve this problem by solving the equations, and takinf them to the slope-intercept form and compare their slopes.
if you solve -3x-18y = 6 for Y, then you get m = (-1/6)
(a). y = (-1/6)x-(1/3)
if you solve 6x-y = 14 for Y, then you get m = (6)
(b). y = (6)x - 14
The relationship between both slopes is that if you multiply them, then you will get -1.
This tells you that the lines are perpendicular.
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