SOLUTION: I have a question involving Algebra 1
A rental company charges a flat fee of x dollers plus y dollers per hour used
one customer used 4 hours and had a fee of 63 dollers
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A rental company charges a flat fee of x dollers plus y dollers per hour used
one customer used 4 hours and had a fee of 63 dollers
Anoth
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Question 180497: I have a question involving Algebra 1
A rental company charges a flat fee of x dollers plus y dollers per hour used
one customer used 4 hours and had a fee of 63 dollers
Another stayed for 6 hours and had a fee of 87 dollers
Please explain what steps i should take first and what method i must use.
please explain Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! let x be the flat fee and y be the additional fee
:
x+4y=63.........eq 1
x+6y=87.........eq 2
:
subtract all terms from eq 2 from eq 1
:
x terms will be eliminated because x-x=0. We are left with 4y-6y=63-87
:
-2y=-24
: additional fee
:
take y's found value and plug it into either eq 1 or 2
:
I am using eq 1
:
x+4(12)=63
: flat fee
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