Question 180466: Trinidadhas $2.35 in nickels and dimes. if she has 33 coins in all , find the number of nickels and dimes. Found 2 solutions by stanbon, Mathtut:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Trinidad has $2.35 in nickels and dimes. if she has 33 coins in all , find the number of nickels and dimes.
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Quantity Equation: n + d = 33
Value Equaltion..:5n +10d = 235 cents
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Modify:
5n + 5d = 165
5n + 10d = 235
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Subtract 1st from 2nd to solve for "d":
5d = 70
d = 14 (# of dimes)
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Substiute into n+d = 33 to solve for "n":
n + 14 = 33
n = 19 (# of nickels)
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Cheers,
Stan H.
You can put this solution on YOUR website! Trinidadhas $2.35 in nickels and dimes. if she has 33 coins in all , find the number of nickels and dimes.
:
lets call the number of nickels and dimes, n and d , respectively
:
n+d=33.............eq 1
.05n+.1d=2.35......eq 2
:
rewrite eq 1 to n=33-d and plug that value into eq 2
:
.05(33-d)+.1d=2.35
:
1.65-.5d+.1d=2.35
:
.05d=.7
: number of dimes
: number of nickels
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