SOLUTION: x+5(squarerootx)-10=2(squarerootx)

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Question 180270: x+5(squarerootx)-10=2(squarerootx)
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
x%2B5sqrt%28x%29-10+=+2sqrt%28x%29 First subtract 2sqrt%28x%29 from both sides.
x%2B3sqrt%28x%29-10+=+0 Now add 10 to both sides.
x%2B3sqrt%28x%29+=+10 Next, subtract x from both sides to leave the 3sqrt%28x%29 by itself.
3sqrt%28x%29+=+10-x Now square both sides.
9x+=+100-20x%2Bx%5E2 Subtract 9x from both sides.
x%5E2-29x%2B100+=+0 Factor the trinomial.
%28x-4%29%28x-25%29+=+0 Apply the zero product rule.
x-4+=+0 or x-25+=+0 so...
highlight%28x+=+4%29 or highlight%28x+=+25%29 But notice that while x = 4 is a valid root, x = 25 is an "extraneous" root introduced during the process by squaring, so x=25 does not work.