You can put this solution on YOUR website! Find sin B and cot B if cosB=-1/4 and tan B>0.
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If cos(B) = -1/4, x=-1 and r = 4
Then y = sqrt(r^2 - x^2) = sqrt(16-1) = sqrt(15)
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So sin(B) = y/r = sqrt(15)/4
and cot(B) = x/y = -1/sqrt(15)
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Cheers,
Stan H.
You can put this solution on YOUR website! IF sin B=a/c, cos B=b/c, and tan B=a/b, then
cosB=-1/4 so b=-1 c=4
tan B=a/b... for tan B>0, a<0 since b<0.
sin B=
cot B=
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HyperBrain!
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Calculations in the post by @HyperBrain are incorrect.
In whole, his solution is total mess.
For correct solution, see my post below.
Since cos(B) is negative and tan(B) is positive (given), we conclude from it that
angle B is in QIII.
In QIII sine is negative, so we write
sin(B) = = = = .
Hence, cot(B) = = = = .
ANSWER. sin(B) = , cot(B) = .
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