SOLUTION: Find the equation, in standard form, of the line perpendicular to 2x - 3y = -5 and passing through (3, -2). Write the equation in standard form, with all integer coefficients.
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-> SOLUTION: Find the equation, in standard form, of the line perpendicular to 2x - 3y = -5 and passing through (3, -2). Write the equation in standard form, with all integer coefficients.
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Question 180056: Find the equation, in standard form, of the line perpendicular to 2x - 3y = -5 and passing through (3, -2). Write the equation in standard form, with all integer coefficients.
Explain your answer. Answer by HyperBrain(694) (Show Source):
You can put this solution on YOUR website! 2x - 3y = -5
2x=3y-5
3y-5=2x
3y=2x+5
y=2x/3+5/3
since the line has slope 2/3, the line perpendicular to it has slope -3/2.
Using the point (3,-2),
y+2=-3/2(x-3)
2y+4=-3x+9
3x+2y-5=0
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