SOLUTION: A 60% antifreeze solution is to be mixed with a 10% antifreeze solution. In what ratio (x/y) must they be mixed to obtain a 40% antifreeze solution?(hint: Let N be the number of li
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Question 179768: A 60% antifreeze solution is to be mixed with a 10% antifreeze solution. In what ratio (x/y) must they be mixed to obtain a 40% antifreeze solution?(hint: Let N be the number of litres of the 40% solution) Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! so let N be the number of liters of 40% solution.
:
let x and y be the amount of mixture of 60% and 10% solutions respectively
:
x+y=N........eq 1
.6x+.1y=.4N..eq 2
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rewrite eq 1 to x=N-y and plug that value into eq 2
:
.6(N-y)+.1y=.4N
:
.6N-.6y+.1y=.4N
:
-.5y=-.2N
:
y=.4N
:
x=N-.4N=.6N
:
x/y=.6N/.4N=3/2
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so the ratio is 3 to 2
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