SOLUTION: Mark invested $1500;part at 5%and part at 7%.Question 1... Mark earned $504 interest on an investment at 5% and another at 7%.Number 2.

Algebra ->  Linear-equations -> SOLUTION: Mark invested $1500;part at 5%and part at 7%.Question 1... Mark earned $504 interest on an investment at 5% and another at 7%.Number 2.      Log On


   

Question 179759: Mark invested $1500;part at 5%and part at 7%.Question 1...
Mark earned $504 interest on an investment at 5% and another at 7%.Number 2.
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
thats better!!!!
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let x and y be the amounts invested at 5% and 7% respectively
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x+y=1500..............eq 1
.05x+.07y=504.........eq 2
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this is the way this problem would be written up .But there is a problem
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The scenario as written is IMPOSSIBLE
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1500 at 5% is 75 dollars
1500 at 7% is 105 dollars
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as you can see no combination of money invested in this scenario will come close to 504 dollars
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and 15000 would be too much.
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please re check the question again and submit it as it reads:
thanks Mathtut