SOLUTION: Gideon is 30 years younger than his Father. His mother is three times as old as her son. Find Gideon's age if his father is two years older than his mother.
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Question 179714: Gideon is 30 years younger than his Father. His mother is three times as old as her son. Find Gideon's age if his father is two years older than his mother. Answer by ptaylor(2198) (Show Source):
You can put this solution on YOUR website! Let x=Father's age
x-30=Gideon's age
3(x-30)=Mother's age
Now we are told the following:
x=3(x-30)+2 get rid of parens(distributive)
x=3x-90+2 subtract 3x from each side
x-3x=3x-3x-90+2 collect like terms
-2x=-88 divide each side by -2
x=44--------------------------------Father's age
x-30=44-30=14--------------------------------Gideon's age
3*14=42-------------------------------------Mother's age
CK
44=42+2
44=44
Hope this helps---ptaylor
