SOLUTION: 5(x+3)+9 < or = to 3 (x-2)+6
5x+15+9 < or = to 3x-6+6
5x+24 < or = to 3x
5x/3x+24 < or = to 3x/3x
this is where I get hung up what do I do with the 5x/3x?
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-> SOLUTION: 5(x+3)+9 < or = to 3 (x-2)+6
5x+15+9 < or = to 3x-6+6
5x+24 < or = to 3x
5x/3x+24 < or = to 3x/3x
this is where I get hung up what do I do with the 5x/3x?
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Question 17960: 5(x+3)+9 < or = to 3 (x-2)+6
5x+15+9 < or = to 3x-6+6
5x+24 < or = to 3x
5x/3x+24 < or = to 3x/3x
this is where I get hung up what do I do with the 5x/3x?
You can put this solution on YOUR website! Well, you got started ok but your fourth step is in error. You must collect the x-terms (5x & 3x) together on the same side of the = sign.
At this point, you can subtract 24 from both sides. Now, subtract 3x from both sides. Finally, divide both sides by 2.
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