SOLUTION: Tom's home is 1,800 m from his school. One morning he walked part of the way to school and then ran the rest. If it took him 20 minutes or less to get to school, and he walks at 70

Algebra ->  Human-and-algebraic-language -> SOLUTION: Tom's home is 1,800 m from his school. One morning he walked part of the way to school and then ran the rest. If it took him 20 minutes or less to get to school, and he walks at 70      Log On


   



Question 179569: Tom's home is 1,800 m from his school. One morning he walked part of the way to school and then ran the rest. If it took him 20 minutes or less to get to school, and he walks at 70m/min and runs 210m/min, how far did he run?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I will write 2 equations:
1 for running
1 for walking
(1) d%5Bw%5D+=+r%5Bw%5D%2At%5Bw%5D
(2) d%5Br%5D+=+r%5Br%5D%2At%5Br%5D
given:
r%5Bw%5D+=+70 m/min
r%5Br%5D+=+210 m/min
d%5Bw%5D+%2B+d%5Br%5D+=+1800 m
t%5Bw%5D+%2B+t%5Br%5D+%3C=+20min
--------------------------
I can rewrite (1) and (2):
(1) d%5Bw%5D+=+70t%5Bw%5D m
(2) d%5Br%5D+=+210t%5Br%5D m
Now, from
d%5Bw%5D+%2B+d%5Br%5D+=+1800 I get
d%5Br%5D+=+1800+-+d%5Bw%5D
I'll substitute this in (2)
(2) 1800+-+d%5Bw%5D+=+210t%5Br%5D m
{2) d%5Bw%5D+=+1800+-+210t%5Br%5D m
I'll subtract (1) from (2):
{2) d%5Bw%5D+=+1800+-+210t%5Br%5D
(1) -d%5Bw%5D+=+-70t%5Bw%5D
0+=+1800+-+210t%5Br%5D+-+70t%5Bw%5D
70t%5Bw%5D+%2B+210t%5Br%5D+=+1800
Divide both sides by 10
(3) 7t%5Bw%5D+%2B+21t%5Br%5D+=+180
from
t%5Bw%5D+%2B+t%5Br%5D+%3C=+20min
If t%5Bw%5D+%2B+t%5Br%5D+=+20min
Multiply each side by 7
(4) 7t%5Bw%5D+%2B+7t%5Br%5D+=+140min
Subtract (4) from (3)
(3) 7t%5Bw%5D+%2B+21t%5Br%5D+=+180
(4) -7t%5Bw%5D+-+7t%5Br%5D+=+-140
14t%5Br%5D+=+40
t%5Br%5D+=+20%2F7 min
and,since
t%5Bw%5D+%2B+t%5Br%5D+=+20min
t%5Bw%5D+=+20+-+t%5Br%5D
t%5Bw%5D+=+20+-+20%2F7
t%5Bw%5D+=+%28140+-+20%29%2F7
t%5Bw%5D+=+120%2F7 min
The problem wants to know how far he ran
(2) d%5Br%5D+=+210t%5Br%5D m
d%5Br%5D+=+210%2A%2820%2F7%29 m
d%5Br%5D+=+600 m
He ran 600 m
check answer:
I can rewrite (1) and (2):
(1) d%5Bw%5D+=+70t%5Bw%5D m
d%5Bw%5D+=+70%2A%28120%2F7%29 m
d%5Bw%5D+=+1200 m
And, since
d%5Bw%5D+%2B+d%5Br%5D+=+1800 m
600+%2B+1200+=+1800
1800+=+1800
OK
I also looked at
t%5Bw%5D+%2B+t%5Br%5D+%3C=+20min
If he spent a little more time running than
walking, say
t%5Br%5D+=+21%2F7
and
t%5Bw%5D+=+119%2F7
d%5Bw%5D+%2B+d%5Br%5D+=+1820 m
If he spent a little more time walking than running
t%5Br%5D+=+19%2F7
t%5Bw%5D+=+121%2F7
d%5Bw%5D+%2B+d%5Br%5D+=+1780 m
So, he has to spend at least as much time running
as he did