SOLUTION: i need help. can you please help me? thank you so much. here is the problem: a baker has 2 pans with the same area. 1 pan is square and the other is 6 cm narrower and 8 cm longer

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: i need help. can you please help me? thank you so much. here is the problem: a baker has 2 pans with the same area. 1 pan is square and the other is 6 cm narrower and 8 cm longer      Log On


   

Question 179492: i need help. can you please help me? thank you so much. here is the problem:
a baker has 2 pans with the same area. 1 pan is square and the other is 6 cm narrower and 8 cm longer than the square pan. find the area of each pan.
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = length of one side of square pan
then
the area of the square pan is x^2
.
The other pan's area is:
(x-6)(x+8)
.
So we now have:
x^2 = (x-6)(x+8)
FOIL the right:
x^2 = x^2+8x-6x-48
0 = 8x-6x-48
0 = 2x-48
48 = 2x
24 cm = x
So, the square pan is 24 cm by 24 cm
area is 576 square cm
.
The other pan is:
(x-6) by (x+8)
(24-6) by (24+8)
18 cm by 32 cm (size of other pan)
area is 576 square cm