SOLUTION: i seem to be having trouble finding the answer can i get any help please? 25y^2-49w^2 thank you so much

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: i seem to be having trouble finding the answer can i get any help please? 25y^2-49w^2 thank you so much      Log On


   

Question 179426: i seem to be having trouble finding the answer can i get any help please?
25y^2-49w^2
thank you so much
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

25y%5E2-49w%5E2 Start with the given expression.


%285y%29%5E2-49w%5E2 Rewrite 25y%5E2 as %285y%29%5E2.


%285y%29%5E2-%287w%29%5E2 Rewrite 49w%5E2 as %287w%29%5E2.


Notice how we have a difference of squares A%5E2-B%5E2 where in this case A=5y and B=7w.


So let's use the difference of squares formula A%5E2-B%5E2=%28A%2BB%29%28A-B%29 to factor the expression:


A%5E2-B%5E2=%28A%2BB%29%28A-B%29 Start with the difference of squares formula.


%285y%29%5E2-%287w%29%5E2=%285y%2B7w%29%285y-7w%29 Plug in A=5y and B=7w.


So this shows us that 25y%5E2-49w%5E2 factors to %285y%2B7w%29%285y-7w%29.


In other words 25y%5E2-49w%5E2=%285y%2B7w%29%285y-7w%29.