Question 179277: In a two digit number, twice the tens digit increased by the units digit is 22. If the digits are reversed, the new number is 45 less than the original.( please can you show the work)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! In a two digit number, twice the tens digit increased by the units digit is 22. If the digits are reversed, the new number is 45 less than the original
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Let the number be 10t + u where t is the ten and u is the unit digit.
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Equations:
2t+u = 22
10u + t = 10t + u - 45
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Rearrange to get:
2t + u = 22
9t - 9u = 45
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Simplify:
2t + u = 22
t - u = 5
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Add to solve for t:
3t = 27
t = 9 (the tens digit)
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Since t-u = 5, 9 - u = 5 ; u = 4
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Original Number:
10t + u = 10*9 + 4 = 94
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Cheers,
Stan H.
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