SOLUTION: Ok, shhhhhhhhhhh I am a 48 year old, 26 year veteran second grade teacher taking a math class. Yeah, I am wondering the same thing too WHY? I want to learn this but it is really r

Algebra ->  Graphs -> SOLUTION: Ok, shhhhhhhhhhh I am a 48 year old, 26 year veteran second grade teacher taking a math class. Yeah, I am wondering the same thing too WHY? I want to learn this but it is really r      Log On


   



Question 179162: Ok, shhhhhhhhhhh I am a 48 year old, 26 year veteran second grade teacher taking a math class. Yeah, I am wondering the same thing too WHY? I want to learn this but it is really really hard. I had this in class. It made sense then but it does not now. I have tried doing my homework right after the class but I am plain brain dead and so relieved the 8am-5pm class is over I don’t! I have a renewed understanding of students that struggle.
Taking a deep breath, here it is: Let L3 denote the straight line passing through the points p1(1,3) and p2(-5,5).
Find the slope of L3, find the y intercept of L3, the slope y- intercept form of the equation of L3 is_________.
2. Let L4 denote the straight line passing through the points P3(-3,3) and P4(1,-3). Find the slope of L4. Find y intercept of L4. The slope y-intercept form of the equation of L4 is _______.
3. On the coordinate grid, graph L3 and L4. Use visual observation to approximate the point of intersection of L3 and L4. Use algebra to find the exact point of intersection of L3 and L4.
4. Find the equation of the line parallel to L3 that passes through the origin (0,0). Find the equation of the straight line that is parallel to the line L4 an passes through the point (-2,-5). Ok I guess that is my 4 allowed questions :)Thank you in advance.

Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Let L3 denote the straight line passing through the points p1(1,3) and
p2(-5,5).
1. Find the slope of L3, find the y intercept of L3, the slope y- intercept
slope = (5-2)/(1--5) = 3/6 = 1/2
intercept:
Form of equation is y = mx + b
You know y=3 when x=1; you know m=1/2; so solve for "b", the intercept.
3 = (1/2)1 + b
b = 5/2
----------
form of the equation of L3 is y = (1/2)x + (5/2)
=========================================================
2. Let L4 denote the straight line passing through the points P3(-3,3) and P4(1,-3).
Find the slope of L4.
m = (3--3)/(-3-1) = 6/-4 = -3/2
Find y intercept of L4.
Since y = mx+b, 3=(-3/2)(-3) + b
b = 3 - 9/2
b = -3/2
----
The slope y-intercept form of the equation of L4 is y = (-3/2)x -(3/2)
------------------------------------------------------------------------
3. On the coordinate grid, graph L3 and L4. Use visual observation to approximate the point of intersection of L3 and L4. Use algebra to find the exact point of intersection of L3 and L4.

------------------------------------------------------------------------
4. Find the equation of the line parallel to L3 that passes through the origin (0,0). Find the equation of the straight line that is parallel to the line L4 an passes through the point (-2,-5).
L3 has slope = 1/2 so the equation you want must have slope = 1/2
----
You have slope and a point:
-5 = (1/2)(-2) + b
b = -4
Equation: y = (1/2)x - 4
============================
Cheers,
Stan H.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(1)
Start with the general slope-intercept form of
a straight line, which is
y+=+mx+%2B+b
where m= slope
and b= y-intercept
You are given points in the form (x,y),
p1(1,3)
p2(-5,5)
You can substitute these x-y pairs directly in the formula
(1) 3+=+m%2A1+%2B+b
(2) 5+=+m%2A%28-5%29+%2B+b
You have 2 equations and 2 unknowns, so it's solvable
Subtract (1) from (2)
(2) -5m+%2B+b+=+5
(1) -m+-+b+=+-3
-6m+=+2
m+=+-%281%2F3%29
Now plug this result back into (1)
(1) 3+=+-%281%2F3%29+%2B+b
9+=+-1+%2B+3b
3b+=+10
b+=+10%2F3 this is the y-intercept
The equation of the line is
y+=+-%281%2F3%29x+%2B+10%2F3
---------
Part (2) is just a repetition of this process
In part (4), just make m the same for both lines
and use the given points to find parallel lines