SOLUTION: A motorcycle breaks down and the rider has to walk the rest of the way to work. The motorcycle was traveling at 45mi/h, and the rider walks at a speed of 6 mi/h. The distance from

Algebra ->  Expressions-with-variables -> SOLUTION: A motorcycle breaks down and the rider has to walk the rest of the way to work. The motorcycle was traveling at 45mi/h, and the rider walks at a speed of 6 mi/h. The distance from       Log On


   



Question 178877: A motorcycle breaks down and the rider has to walk the rest of the way to work. The motorcycle was traveling at 45mi/h, and the rider walks at a speed of 6 mi/h. The distance from home to work is 25 miles, and the total time for the trip was 2 hours. How far did the motorcycle go before it broke down?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let t= the time on the motorcycle
Let d= the distance travelled on the motorcycle
d%2F45+%2B+%2825+-+d%29%2F6+=+2
Multiply both sides by 90
2d+%2B+15%2A%2825+-+d%29+=+180
2d+%2B+375+-+15d+=+180
13d+=+375+-+180
13d+=+195
d+=+15
The motorcycle went 15 mi before it broke down
check:
d%2F45+%2B+%2825+-+d%29%2F6+=+2
15%2F45+%2B+%2825+-+15%29%2F6+=+2
15%2F45+%2B+10%2F6+=+2
2%2A15+%2B+10%2A15+=+2%2A90
30+%2B+150+=+180
180+=+180
OK