SOLUTION: Could you please help me with these fractions: Find the lowest terms of the following fractions 1) 4/16 = 2) 8/56 = 3) 3/27 = 4) 15/45 = Thank you so much!!!!!!!!!!

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: Could you please help me with these fractions: Find the lowest terms of the following fractions 1) 4/16 = 2) 8/56 = 3) 3/27 = 4) 15/45 = Thank you so much!!!!!!!!!!      Log On


   

Question 178861: Could you please help me with these fractions:
Find the lowest terms of the following fractions
1) 4/16 =
2) 8/56 =
3) 3/27 =
4) 15/45 =
Thank you so much!!!!!!!!!!!!!!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
# 1

Solved by pluggable solver: Reducing Fractions Calculator
In order to reduce 4%2F16, the numerator and denominator must share a common factor. This common number must evenly divide into both of them without any remainder or decimal.


In order to completely reduce the fraction, you must divide the numerator and the denominator by the greatest common factor (GCF). The GCF of 4 and 16 is (note: click here if you need help with finding the GCF). So divide both the numerator and denominator by



In other words, to reduce the fraction you do this
%28numerator%2FGCF%29%2F%28denominator%2FGCF%29=Reduced_Fraction



%284%2F%29%2F%2816%2F%29 Plug in the numerator, denominator, and the GCF


%281%29%2F%2816%2F%29 Now divide 4 by to get 1. This is now the new numerator.


1%2F4 Now divide 16 by to get 4. This is now the new denominator.



So

%284%2F%29%2F%2816%2F%29=1%2F4




This means that 4%2F16 reduces to 1%2F4



In other words, 4%2F16=1%2F4





---------------------------------


# 2

Solved by pluggable solver: Reducing Fractions Calculator
In order to reduce 8%2F56, the numerator and denominator must share a common factor. This common number must evenly divide into both of them without any remainder or decimal.


In order to completely reduce the fraction, you must divide the numerator and the denominator by the greatest common factor (GCF). The GCF of 8 and 56 is (note: click here if you need help with finding the GCF). So divide both the numerator and denominator by



In other words, to reduce the fraction you do this
%28numerator%2FGCF%29%2F%28denominator%2FGCF%29=Reduced_Fraction



%288%2F%29%2F%2856%2F%29 Plug in the numerator, denominator, and the GCF


%281%29%2F%2856%2F%29 Now divide 8 by to get 1. This is now the new numerator.


1%2F7 Now divide 56 by to get 7. This is now the new denominator.



So

%288%2F%29%2F%2856%2F%29=1%2F7




This means that 8%2F56 reduces to 1%2F7



In other words, 8%2F56=1%2F7





---------------------------------



# 3

Solved by pluggable solver: Reducing Fractions Calculator
In order to reduce 3%2F27, the numerator and denominator must share a common factor. This common number must evenly divide into both of them without any remainder or decimal.


In order to completely reduce the fraction, you must divide the numerator and the denominator by the greatest common factor (GCF). The GCF of 3 and 27 is (note: click here if you need help with finding the GCF). So divide both the numerator and denominator by



In other words, to reduce the fraction you do this
%28numerator%2FGCF%29%2F%28denominator%2FGCF%29=Reduced_Fraction



%283%2F%29%2F%2827%2F%29 Plug in the numerator, denominator, and the GCF


%281%29%2F%2827%2F%29 Now divide 3 by to get 1. This is now the new numerator.


1%2F9 Now divide 27 by to get 9. This is now the new denominator.



So

%283%2F%29%2F%2827%2F%29=1%2F9




This means that 3%2F27 reduces to 1%2F9



In other words, 3%2F27=1%2F9





---------------------------------


# 4

Solved by pluggable solver: Reducing Fractions Calculator
In order to reduce 15%2F45, the numerator and denominator must share a common factor. This common number must evenly divide into both of them without any remainder or decimal.


In order to completely reduce the fraction, you must divide the numerator and the denominator by the greatest common factor (GCF). The GCF of 15 and 45 is (note: click here if you need help with finding the GCF). So divide both the numerator and denominator by



In other words, to reduce the fraction you do this
%28numerator%2FGCF%29%2F%28denominator%2FGCF%29=Reduced_Fraction



%2815%2F%29%2F%2845%2F%29 Plug in the numerator, denominator, and the GCF


%281%29%2F%2845%2F%29 Now divide 15 by to get 1. This is now the new numerator.


1%2F3 Now divide 45 by to get 3. This is now the new denominator.



So

%2815%2F%29%2F%2845%2F%29=1%2F3




This means that 15%2F45 reduces to 1%2F3



In other words, 15%2F45=1%2F3





---------------------------------


If you need more help with reducing fractions, check out this solver.