SOLUTION: a sign has a area of 60ft squared. if the width of is 4 ft shorter then the length, what are the dimensions of the sighn?
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-> SOLUTION: a sign has a area of 60ft squared. if the width of is 4 ft shorter then the length, what are the dimensions of the sighn?
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You can put this solution on YOUR website! a sign has a area of 60ft squared. if the width of is 4 ft shorter then the length, what are the dimensions of the sign?
:
let x = width of the sign
then
(x+4) = length of the sign
;
:
W * L = area
x(x+4) = 60
:
x^2 + 4x = 60
;
x^2 + 4x - 60 = 0; a quadratic equation
Factor this to:
(x+10)(x-6) = 0
positive solution is what we want here
x = 6 ft is the width
then
6 + 4 = 10 ft is the length
:
:
Check solution by finding the area: 10 * 6 = 60 sq/ft
