SOLUTION: A bicycle rider travels 18 miles in the same amount of time that it takes a jogger to travel 10 miles. If the bicyclist goes 9.6 miles per hour faster than the jogger, how fast doe

Algebra ->  Equations -> SOLUTION: A bicycle rider travels 18 miles in the same amount of time that it takes a jogger to travel 10 miles. If the bicyclist goes 9.6 miles per hour faster than the jogger, how fast doe      Log On


   

Question 178780: A bicycle rider travels 18 miles in the same amount of time that it takes a jogger to travel 10 miles. If the bicyclist goes 9.6 miles per hour faster than the jogger, how fast does each person travel?
Found 2 solutions by tutor318, Mathtut:
Answer by tutor318(1) About Me  (Show Source):
You can put this solution on YOUR website!
ok you have to do a propotion so 18miles ove 10 miles on one side on the other nine and six tenths on the top (9.6) you get 96

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
A bicycle rider travels 18 miles in the same amount of time that it takes a jogger to travel 10 miles. If the bicyclist goes 9.6 miles per hour faster than the jogger, how fast does each person travel?
:
distance = rate * time
:
let r be the rate of the jogger...therefore rate of the bike rider is r+9.6
times are equal
:
bike:18=(r+9.6)t...eq 1
jogger:10=rt.......eq 2
:
rewrite eq 2 to t=10/r and plug that into eq 1
:
18=(r+9.6)(10/r)
:
18r=10(r+9.6)......multiplied both sides by r
:
18r=10r+96
:
8r=96
:
highlight%28r=12%29mph-speed of jogger
:
highlight%28r%2B9.6=12%2B9.6=21.6%29mph-speed of bike rider