SOLUTION: May I have some help on this please? I'm just not getting it.: (4-8x)(4+8x)= This is what I've tried: 4(4) + 4(-8) + (-8)4 +(-8)x=16+32x-32x+32x=16+32x

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: May I have some help on this please? I'm just not getting it.: (4-8x)(4+8x)= This is what I've tried: 4(4) + 4(-8) + (-8)4 +(-8)x=16+32x-32x+32x=16+32x      Log On


   



Question 17855: May I have some help on this please? I'm just not getting it.:
(4-8x)(4+8x)=
This is what I've tried:
4(4) + 4(-8) + (-8)4 +(-8)x=16+32x-32x+32x=16+32x

Answer by LilSkittleMd(119) About Me  (Show Source):
You can put this solution on YOUR website!
Use FOIL (first, outer, inner, last) to solve
(4-8x)(4+8x)
4(4)+8x(4)-8x(4)-8x(8x)
16+32x-32x-64x^2
16-64x^2