SOLUTION: can someone please help me with this problem Draw l1 through (-4, 0) and (0, 6). What is the slope of any line parallel to l1? Draw l2 through the origin and parallel to l1

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Question 178536: can someone please help me with this problem

Draw l1 through (-4, 0) and (0, 6). What is the slope of any
line parallel to l1? Draw l2 through the origin and parallel to l1

Found 2 solutions by solver91311, ankor@dixie-net.com:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


To make your drawing, just plot the two points and then draw a line through both of them.



Any line parallel to this line has the same slope. So you need to calculate the slope of this line.

The slope of a line passing through two points and is given by:

.

Your points are: and , so just plug in the values and do the arithmetic:

. You can do your own arithmetic. You don't absolutely have to reduce the fraction to lowest terms, but it makes things much tidier if you do.

To make it easy to create your second line, you need another point on your second line -- you are already given the first one, the origin .

Use the point-slope form of the equation of a line, to create an equation for your second line. Since the slopes have to be the same so that the lines are parallel, use the value of you calculated above and insert the coordinates of the origin for and . Like this:

which simplified is ( being replaced by the value you calculated above) . Now pick any value for that you like other than zero (I would pick 2 myself, but it is entirely up to you), and calculate the value of . These two values will give you the coordinates of a second point for your new line. Plot the new point, plot the origin, and connect the dots.

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Draw l1 through (-4, 0) and (0, 6). What is the slope of any
line parallel to l1? Draw l2 through the origin and parallel to l1
:
Find the slope using the given coordinates: m = %28y2-y1%29%2F%28x2-x1%29
x1=-4; y1=0
x2=0; y2=6
m = %286-0%29%2F%280-%28-4%29%29 = 6%2F%28%2B4%29 = 3%2F2
:
find the equation by using the point/slope equation: y-y1 = m(x-x1)
y - 0 = 3%2F2(x -(-4))
y = 3%2F2(x + 4))
y = 3%2F2x + 6
:
Graph this equation (L1):
+graph%28+300%2C+200%2C+-6%2C+6%2C+-4%2C+10%2C+1.5x%2B6%29+
:
Parallel lines have the same slope 3%2F2 in this case
:
The parallel line thru the origin (0,0) would be y = 3%2F2x
add to the graph L2
+graph%28+300%2C+200%2C+-6%2C+6%2C+-4%2C+10%2C+1.5x%2B6%2C+1.5x%29+