SOLUTION: Thanks in advance for your help evaluating this expression log(3) 243

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Question 178281This question is from textbook college algebras
: Thanks in advance for your help evaluating this expression
log(3) 243
 This question is from textbook college algebras

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
log%283%2C%28243%29%29 Start with the given logarithm.


log%283%2C%283%5E5%29%29 Rewrite 243 as 3%5E5. Note: 3%5E5=243. The key here is the base is 3 and the base of the log is 3


5%2Alog%283%2C%283%29%29 Rewrite the expression using the identity log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29


5%2A1 Evaluate the log base 3 of 3 to get 1. Note: log%28b%2C%28b%29%29=1 where b%3E0


5 Multiply


So log%283%2C%28243%29%29=5