SOLUTION: a woman driving a car 12ft long is passing a truck 32 ft long. the truck is traveling at 50mi/h. how fast must the woman drive her car so that she can pass the truck completely in
Algebra ->
Pythagorean-theorem
-> SOLUTION: a woman driving a car 12ft long is passing a truck 32 ft long. the truck is traveling at 50mi/h. how fast must the woman drive her car so that she can pass the truck completely in
Log On
Question 178157: a woman driving a car 12ft long is passing a truck 32 ft long. the truck is traveling at 50mi/h. how fast must the woman drive her car so that she can pass the truck completely in 6 sec. (Use feet and seconds instead of miles and hours.) Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! a woman driving a car 12ft long is passing a truck 32 ft long. the truck is traveling at 50mi/h. how fast must the woman drive her car so that she can pass the truck completely in 6 sec. (Use feet and seconds instead of miles and hours.)
----------------
The distance from the point where the car's front is adjacent to the truck's rear to where the car's rear is adjacent to the front of the truck is:
12+32+12 feet = 56 feet.
To travel that distance in 6 seconds she must go 50 mph + 56/6 ft/sec.
To convert mph to ft/sec, multiply it by 22/15 (you can work that out or take my word for it).
So her speed must be 50*(22/15) + 56/6 feet/second
= 1100/15 + 28/3
= 220/3 + 28/3
= 248/3 feet/second, or 82.667 fps
----------------
For mph, that's (248/3)*(15/22)
= 1240/22
= 56.36 mph.
