SOLUTION: AT 930 AM ANDREW LEFT EXETER FOR PORTSMOUTH ,CYCLING AT 12 MPH AT 10 AM STACY LEFT PORTSMOUTH FOR EXETER,CYCLING AT 16 MPH.THE DISTANCE FROM EXETER TO PORTSMOUTH IS 20 MILES.FIND T

Algebra ->  Formulas -> SOLUTION: AT 930 AM ANDREW LEFT EXETER FOR PORTSMOUTH ,CYCLING AT 12 MPH AT 10 AM STACY LEFT PORTSMOUTH FOR EXETER,CYCLING AT 16 MPH.THE DISTANCE FROM EXETER TO PORTSMOUTH IS 20 MILES.FIND T      Log On


   

Question 178071: AT 930 AM ANDREW LEFT EXETER FOR PORTSMOUTH ,CYCLING AT 12 MPH AT 10 AM STACY LEFT PORTSMOUTH FOR EXETER,CYCLING AT 16 MPH.THE DISTANCE FROM EXETER TO PORTSMOUTH IS 20 MILES.FIND THE TIME THEY MEET.
THIS IS WHAT I HAVE AM I ON THE RIGHT TRACK? 12T 16 (T-1/2)=20 MILES
12T 16T -8=20
18T-8=20
18T=28
T=1.555555556
THEY WILL MEET AT 11 35 AM??????
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
AT 930 AM ANDREW LEFT EXETER FOR PORTSMOUTH ,CYCLING AT 12 MPH AT 10 AM STACY LEFT PORTSMOUTH FOR EXETER,CYCLING AT 16 MPH.THE DISTANCE FROM EXETER TO PORTSMOUTH IS 20 MILES.FIND THE TIME THEY MEET.
THIS IS WHAT I HAVE AM I ON THE RIGHT TRACK? 12T + 16(T-1/2)=20 MILES
12T + 16T -8=20
28T = 28
T = 1 hr
9:30 + 1 hr = 10:30 AM
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Cheers,
Stan H.