SOLUTION: A SPEEDBOAT COULD TRAVEL AT 5 TIMES THE SPEED OF A CURRENT. THUS, IT COULD TRAVEL 300 MILES DOWNRIVER IN 2 HOURS MORE THAN IT TOOK TO TRAVEL 150 MILES UPRIVER. WHAT WAS THE SPEED O

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Question 178061: A SPEEDBOAT COULD TRAVEL AT 5 TIMES THE SPEED OF A CURRENT. THUS, IT COULD TRAVEL 300 MILES DOWNRIVER IN 2 HOURS MORE THAN IT TOOK TO TRAVEL 150 MILES UPRIVER. WHAT WAS THE SPEED OF THE BOAT IN STILL WATER?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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A SPEEDBOAT COULD TRAVEL AT 5 TIMES THE SPEED OF A CURRENT. THUS, IT COULD
TRAVEL 300 MILES DOWNRIVER IN 2 HOURS MORE THAN IT TOOK TO TRAVEL 150 MILES
UPRIVER. WHAT WAS THE SPEED OF THE BOAT IN STILL WATER?
;
let x = boat speed in still water
:
given that current speed 1%2F5 boat speed, therefore we can say;
.2x = current speed
:
Then
1.2x = speed down stream
.8x = speed up stream
:
write a time equation time = dist%2Fspeed
downstream time = upstream time + 2 hrs
300%2F1.2x = 150%2F.8x + 2
multiply equation by 2.4x to get rid of the denominators
2(300) = 3(150) + 2(2.4x)
:
600 = 450 + 4.8x
:
600 - 450 = 4.8x
:
x = 150%2F4.8
x = 31.25 speed of boat in still water
:
:
Check solution in original equation
300%2F1.2%2831.25%29 = 150%2F.8%2831.25%29 + 2
300%2F37.5 = 150%2F25 + 2
8 = 6 + 2