SOLUTION: My question is Find the length and width of a rectangular lot with a perimeter of 70 meters if the length is 5 meters more than the width.

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Question 177948: My question is Find the length and width of a rectangular lot with a perimeter of 70 meters if the length is 5 meters more than the width.
Found 2 solutions by edjones, jim_thompson5910:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
2L+2w=P
.
L=w+5
2(w+5)+2w=70
2w+10+2w=70
4w+10=70
4w=60
w=15
L=20
.
Ed

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Let W=width and L=length

Since the "length is 5 meters more than the width", this tells us that L=W%2B5 (ie add 5 to the width to get the length)

P=2L%2B2W Start with the perimeter formula


70=2%28W%2B5%29%2B2W Plug in P=70 (the given perimeter) and L=W%2B5


70=2W%2B10%2B2W Distribute


70-10=2W%2B2W Subtract 10 from both sides


60=4W Combine like terms.


60%2F4=W Divide both sides by 4 to isolate "W"


15=W Reduce


So the width is 15 meters


L=W%2B5 Go back to the length equation


L=15%2B5 Plug in W=15


L=20 Add


So the length is 20 meters.


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Answer:

So the length is 20 meters and the width is 15 meters