SOLUTION: 4x^2-4=3x^2-3x
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Question 177610
:
4x^2-4=3x^2-3x
Answer by
kollanag(3)
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4x^2 - 4 = 3x^2 - 3x
x^2 + 3x - 4 = 0
(x-3) (x-1) = 0
so x = 3 or 1